Houston: India’s Vikram Malhotra is on fire. The US- based player, who had only last week won a PSA Challenger event in Canada, added one more to his kitty with the triumph in the Texas Open, a PSA challenger here on Sunday. He beat Daniel Mekbeb of Czeck Republic over five games 11-6, 2-11, 5-11, 15-13, 11-1. This is Vikram’s 8th PSA title overall in his career thus far.
The fourth seeded Indian, who moved ahead after a first-round bye, got past three players enroute to the final. His second round victim was Syed Hamzad Bukhari of Pakistan, followed by Reuben Phillips of England in the quarterfinals and another Pakistani Shahjahan Khan, the 8th seed in the semi-final 11-6, 9-11, 11-5, 11-6.
Incidentally the top seed in this event was Ramit Tandon but he conceded his match in the quarter final to Shahjahan Khan, Vikram’s sem-final victim.